Algorithm

[LeetCode 334] Increasing Triplet Subsequence [Java]

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2017-11-06

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11/06

1. Description

Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.

Formally the function should:

Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.

Your algorithm should run in O(n) time complexity and O(1) space complexity.

2. Example

Given [1, 2, 3, 4, 5],
return true.

Given [5, 4, 3, 2, 1],
return false.

3. Code


public class LeetCode0334 {
    public boolean increasingTriplet(int[] nums) {
        if(nums == null || nums.length < 3){
            return false;
        }
        int x = Integer.MAX_VALUE;
        int y = Integer.MAX_VALUE;
        for(int i =0; i< nums.length;i++){
            if(x >= nums[i]){
                x = nums[i];
            }else if(y >= nums[i]){
                y = nums[i];
            }else{
                return true;
            }
        }
        return false;
    }

    public static void main(String[] args) {
        LeetCode0334 leetcode = new LeetCode0334();
        int[] nums = new int[]{5, 4, 3, 2, 1};
        System.out.println(leetcode.increasingTriplet(nums));
    }
}

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